Samarium
  
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Statistics:
- Name: Samarium
- Symbol: Sm
- Classification: Lanthanide
- Atomic Number: 62
- Atomic Mass: 150.36 g/mol
- Density: 7.54 g/cm3
- Melting: 1072°C
- Boiling: 1778°C
- Protons & Electrons:62
- Neutrons:88
- Discovered: 1879
- Discovered By: Lecoq de Boisbaudran
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Electrons Per Energy Level:
- Level 1: 2
- Level 2: 8
- Level 3: 18
- Level 4: 24
- Level 5: 8
- Level 6: 2
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Isotopes:
Isotope: Half-life
- 144Sm: stable
- 145Sm: 340 days
- 146Sm: 1.03e+8 years
- 147Sm: 1.06e+11 years
- 148Sm: 1.06e+11 years
- 149Sm: 2e+15 years
- 150Sm: stable
- 151Sm: 90 years
- 152Sm: stable
- 153Sm: 46.284 hours
- 154Sm: stable
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Brief Summary
Samarium is a Lanthanide with the symbol 'Sm' and contains 62 Protons & Electrons with 88 neutrons in the nucleus of the atom.
Samarium has an atomic mass of 150.36 g/mol
and, at a temperature of 20°C, has a density of 7.54 g/cm3.
It will melt at a temperature of 1072°C and boil at 1778°C.
Samarium was discovered by Lecoq de Boisbaudran in 1879 and is named 'Samarium' mineral: smarskite.
Some common usages for Samarium: used in magnets, in alloys with cobalt, and nuclear reactors.
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Definitions and Notes
Density listed is at a temperature of 20°C.
Isotopes are forms of an element who have the same atomic number but different mass because they contain different number of neutrons.
Half-life is the time required for a quantity of a subject to fall to half of its current quantity.
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MLA Citing Format
Samarium :: Sm :: 62 - Chemical Element. 22 Nov. 2008 <http://www.chemicalelement.com/element/samarium.html>.
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